Description
https://leetcode.com/problems/find-anagram-mappings/
Given two lists Aand B, and B is an anagram of A. B is an anagram of A means B is made by randomizing the order of the elements in A.
We want to find an index mapping P, from A to B. A mapping P[i] = j means the ith element in A appears in B at index j.
These lists A and B may contain duplicates. If there are multiple answers, output any of them.
For example, given
A = [12, 28, 46, 32, 50] B = [50, 12, 32, 46, 28]
We should return
[1, 4, 3, 2, 0]
as P[0] = 1 because the 0th element of A appears at B[1], and P[1] = 4 because the 1st element of A appears at B[4], and so on.
Note:
A, Bhave equal lengths in range[1, 100].A[i], B[i]are integers in range[0, 10^5].
Explanation
Find A’s numbers’ indices in B.
Python Solution
class Solution:
def anagramMappings(self, A: List[int], B: List[int]) -> List[int]:
results = []
for number in A:
results.append(B.index(number))
return results
- Time Complexity: O(N)
- Space Complexity: O(N)