Description
https://leetcode.com/problems/sentence-similarity/
We can represent a sentence as an array of words, for example, the sentence "I am happy with leetcode"
can be represented as arr = ["I","am",happy","with","leetcode"]
.
Given two sentences sentence1
and sentence2
each represented as a string array and given an array of string pairs similarPairs
where similarPairs[i] = [xi, yi]
indicates that the two words xi
and yi
are similar.
Return true
if sentence1
and sentence2
are similar, or false
if they are not similar.
Two sentences are similar if:
- They have the same length (i.e. the same number of words)
sentence1[i]
andsentence2[i]
are similar.
Notice that a word is always similar to itself, also notice that the similarity relation is not transitive. For example, if the words a
and b
are similar and the words b
and c
are similar, a
and c
are not necessarily similar.
Example 1:
Input: sentence1 = ["great","acting","skills"], sentence2 = ["fine","drama","talent"], similarPairs = [["great","fine"],["drama","acting"],["skills","talent"]] Output: true Explanation: The two sentences have the same length and each word i of sentence1 is also similar to the corresponding word in sentence2.
Example 2:
Input: sentence1 = ["great"], sentence2 = ["great"], similarPairs = [] Output: true Explanation: A word is similar to itself.
Example 3:
Input: sentence1 = ["great"], sentence2 = ["doubleplus","good"], similarPairs = [["great","doubleplus"]] Output: false Explanation: As they don't have the same length, we return false.
Constraints:
1 <= sentence1.length, sentence2.length <= 1000
1 <= sentence1[i].length, sentence2[i].length <= 20
sentence1[i]
andsentence2[i]
consist of lower-case and upper-case English letters.0 <= similarPairs.length <= 1000
similarPairs[i].length == 2
1 <= xi.length, yi.length <= 20
xi
andyi
consist of lower-case and upper-case English letters.- All the pairs
(xi,yi)
are distinct.
Explanation
First compare the length of two sentences. Then check if words in sequences are in pairs.
Python Solution
class Solution:
def areSentencesSimilar(self, sentence1: List[str], sentence2: List[str], similarPairs: List[List[str]]) -> bool:
if len(sentence1) != len(sentence2):
return False
pairs_dict = defaultdict(set)
for pair in similarPairs:
pairs_dict[pair[0]].add(pair[1])
pairs_dict[pair[1]].add(pair[0])
for word1, word2 in zip(sentence1, sentence2):
if word1 != word2 and word2 not in pairs_dict[word1]:
return False
return True
- Time Complexity: O(N).
- Space Complexity: O(N).