Description
https://leetcode.com/problems/binary-search/
Given an array of integers nums
which is sorted in ascending order, and an integer target
, write a function to search target
in nums
. If target
exists, then return its index. Otherwise, return -1
.
Example 1:
Input: nums = [-1,0,3,5,9,12], target = 9 Output: 4 Explanation: 9 exists in nums and its index is 4
Example 2:
Input: nums = [-1,0,3,5,9,12], target = 2 Output: -1 Explanation: 2 does not exist in nums so return -1
Constraints:
1 <= nums.length <= 104
-9999 <= nums[i], target <= 9999
- All the integers in
nums
are unique. nums
is sorted in an ascending order.
Explanation
Just implement a basic binary search to search for the target.
Python Solution
class Solution:
def search(self, nums: List[int], target: int) -> int:
start = 0
end = len(nums) - 1
while start + 1 < end:
mid = start + (end - start) // 2
if nums[mid] == target:
return mid
elif nums[mid] > target:
end = mid
else:
start = mid
if nums[end] == target:
return end
elif nums[start] == target:
return start
return -1
- Time Complexity: O(log(N)).
- Space Complexity: O(1).