Description
https://leetcode.com/problems/license-key-formatting/
You are given a license key represented as a string s
that consists of only alphanumeric characters and dashes. The string is separated into n + 1
groups by n
dashes. You are also given an integer k
.
We want to reformat the string s
such that each group contains exactly k
characters, except for the first group, which could be shorter than k
but still must contain at least one character. Furthermore, there must be a dash inserted between two groups, and you should convert all lowercase letters to uppercase.
Return the reformatted license key.
Example 1:
Input: s = "5F3Z-2e-9-w", k = 4 Output: "5F3Z-2E9W" Explanation: The string s has been split into two parts, each part has 4 characters. Note that the two extra dashes are not needed and can be removed.
Example 2:
Input: s = "2-5g-3-J", k = 2 Output: "2-5G-3J" Explanation: The string s has been split into three parts, each part has 2 characters except the first part as it could be shorter as mentioned above.
Constraints:
1 <= s.length <= 105
s
consists of English letters, digits, and dashes'-'
.1 <= k <= 104
Explanation
Iterate the characters from the string backward and add a ‘-‘ whenever the count is a multiple of k.
Python Solution
class Solution:
def licenseKeyFormatting(self, s: str, k: int) -> str:
s = s.replace('-', '')
results = []
count = 0
for c in s[::-1]:
if count != 0 and count % k == 0:
results.insert(0, '-')
results.insert(0, c.upper())
count += 1
return "".join(results)
- Time Complexity: O(N).
- Space Complexity: O(N).