Description
https://leetcode.com/problems/number-of-steps-to-reduce-a-number-to-zero/
Given a non-negative integer num, return the number of steps to reduce it to zero. If the current number is even, you have to divide it by 2, otherwise, you have to subtract 1 from it.
Example 1:
Input: num = 14 Output: 6 Explanation: Step 1) 14 is even; divide by 2 and obtain 7. Step 2) 7 is odd; subtract 1 and obtain 6. Step 3) 6 is even; divide by 2 and obtain 3. Step 4) 3 is odd; subtract 1 and obtain 2. Step 5) 2 is even; divide by 2 and obtain 1. Step 6) 1 is odd; subtract 1 and obtain 0.
Example 2:
Input: num = 8 Output: 4 Explanation: Step 1) 8 is even; divide by 2 and obtain 4. Step 2) 4 is even; divide by 2 and obtain 2. Step 3) 2 is even; divide by 2 and obtain 1. Step 4) 1 is odd; subtract 1 and obtain 0.
Example 3:
Input: num = 123 Output: 12
Constraints:
0 <= num <= 10^6
Explanation
Just by implementing the step instructions and it would work.
Python Solution
class Solution:
def numberOfSteps (self, num: int) -> int:
steps = 0
while num > 0:
if num % 2 == 0:
num = num // 2
else:
num -= 1
steps += 1
return steps
- Time Complexity: O(N)
- Space Complexity: O(1)