Description
https://leetcode.com/problems/encode-and-decode-tinyurl/
Note: This is a companion problem to the System Design problem: Design TinyURL.
TinyURL is a URL shortening service where you enter a URL such as https://leetcode.com/problems/design-tinyurl
and it returns a short URL such as http://tinyurl.com/4e9iAk
. Design a class to encode a URL and decode a tiny URL.
There is no restriction on how your encode/decode algorithm should work. You just need to ensure that a URL can be encoded to a tiny URL and the tiny URL can be decoded to the original URL.
Implement the Solution
class:
Solution()
Initializes the object of the system.String encode(String longUrl)
Returns a tiny URL for the givenlongUrl
.String decode(String shortUrl)
Returns the original long URL for the givenshortUrl
. It is guaranteed that the givenshortUrl
was encoded by the same object.
Example 1:
Input: url = "https://leetcode.com/problems/design-tinyurl" Output: "https://leetcode.com/problems/design-tinyurl" Explanation: Solution obj = new Solution(); string tiny = obj.encode(url); // returns the encoded tiny url. string ans = obj.decode(tiny); // returns the original url after deconding it.
Constraints:
1 <= url.length <= 104
url
is guranteed to be a valid URL.
Explanation
For encoding, we can convert the long URL to hash code value and store it into a map. For decoding, we just need to use the hash code value from the short URL to get the original long URL.
Python Solution
class Codec:
def __init__(self):
self.map = {}
def encode(self, longUrl: str) -> str:
"""Encodes a URL to a shortened URL.
"""
self.map[str(hash(longUrl))] = longUrl
return "http://tinyurl.com/" + str(hash(longUrl));
def decode(self, shortUrl: str) -> str:
"""Decodes a shortened URL to its original URL.
"""
shortUrl_hash = shortUrl.split("http://tinyurl.com/")[1]
return self.map[shortUrl_hash]
# Your Codec object will be instantiated and called as such:
# codec = Codec()
# codec.decode(codec.encode(url))
- Time Complexity: O(N).
- Space Complexity: O(N).