Description
https://leetcode.com/problems/maximum-69-number/
Given a positive integer num
consisting only of digits 6 and 9.
Return the maximum number you can get by changing at most one digit (6 becomes 9, and 9 becomes 6).
Example 1:
Input: num = 9669 Output: 9969 Explanation: Changing the first digit results in 6669. Changing the second digit results in 9969. Changing the third digit results in 9699. Changing the fourth digit results in 9666. The maximum number is 9969.
Example 2:
Input: num = 9996 Output: 9999 Explanation: Changing the last digit 6 to 9 results in the maximum number.
Example 3:
Input: num = 9999 Output: 9999 Explanation: It is better not to apply any change.
Constraints:
1 <= num <= 10^4
num
‘s digits are 6 or 9.
Explanation
We can convert to string first and replace the first ‘6’ in number with ‘9’.
Python Solution
class Solution:
def maximum69Number (self, num: int) -> int:
result = ""
num_list = list(str(num))
if '6' not in num_list:
return num
index = num_list.index('6')
num_list[index] = '9'
return int("".join(num_list))
- Time Complexity: O(N).
- Space Complexity: O(N).