Description
https://leetcode.com/problems/path-crossing/
Given a string path
, where path[i] = 'N'
, 'S'
, 'E'
or 'W'
, each representing moving one unit north, south, east, or west, respectively. You start at the origin (0, 0)
on a 2D plane and walk on the path specified by path
.
Return True
if the path crosses itself at any point, that is, if at any time you are on a location you’ve previously visited. Return False
otherwise.
Example 1:
Input: path = "NES" Output: false Explanation: Notice that the path doesn't cross any point more than once.
Example 2:
Input: path = "NESWW" Output: true Explanation: Notice that the path visits the origin twice.
Constraints:
1 <= path.length <= 10^4
path
will only consist of characters in{'N', 'S', 'E', 'W}
Explanation
Track the position visited and check if any position revisited.
Python Solution
class Solution:
def isPathCrossing(self, path: str) -> bool:
directions = {
'N': [0, 1],
'S': [0, -1],
'E': [1, 0],
'W': [-1, 0]
}
visited = defaultdict(set)
position = [0, 0]
visited[position[0]].add(position[1])
for c in path:
d = directions[c]
position = [position[0] + d[0], position[1] + d[1]]
if position[0] in visited and position[1] in visited[position[0]]:
return True
visited[position[0]].add(position[1])
return False
- Time Complexity: O(N).
- Space Complexity: O(N).