Description
https://leetcode.com/problems/number-of-different-integers-in-a-string/
You are given a string word
that consists of digits and lowercase English letters.
You will replace every non-digit character with a space. For example, "a123bc34d8ef34"
will become " 123 34 8 34"
. Notice that you are left with some integers that are separated by at least one space: "123"
, "34"
, "8"
, and "34"
.
Return the number of different integers after performing the replacement operations on word
.
Two integers are considered different if their decimal representations without any leading zeros are different.
Example 1:
Input: word = "a123bc34d8ef34" Output: 3 Explanation: The three different integers are "123", "34", and "8". Notice that "34" is only counted once.
Example 2:
Input: word = "leet1234code234" Output: 2
Example 3:
Input: word = "a1b01c001" Output: 1 Explanation: The three integers "1", "01", and "001" all represent the same integer because the leading zeros are ignored when comparing their decimal values.
Constraints:
1 <= word.length <= 1000
word
consists of digits and lowercase English letters.
Explanation
Replace every non-digit character with a space first. Then count how many distinct numbers are there.
Python Solution
class Solution:
def numDifferentIntegers(self, word: str) -> int:
digit_str = ""
for c in word:
if not c.isdigit():
digit_str += " "
else:
digit_str += c
numbers = digit_str.split()
numbers_set = set()
for number in numbers:
numbers_set.add(int(number))
return len(numbers_set)
- Time Complexity: O(N).
- Space Complexity: O(N).