Description
https://leetcode.com/problems/guess-number-higher-or-lower/
We are playing the Guess Game. The game is as follows:
I pick a number from 1
to n
. You have to guess which number I picked.
Every time you guess wrong, I will tell you whether the number I picked is higher or lower than your guess.
You call a pre-defined API int guess(int num)
, which returns 3 possible results:
-1
: The number I picked is lower than your guess (i.e.pick < num
).1
: The number I picked is higher than your guess (i.e.pick > num
).0
: The number I picked is equal to your guess (i.e.pick == num
).
Return the number that I picked.
Example 1:
Input: n = 10, pick = 6 Output: 6
Example 2:
Input: n = 1, pick = 1 Output: 1
Example 3:
Input: n = 2, pick = 1 Output: 1
Example 4:
Input: n = 2, pick = 2 Output: 2
Constraints:
1 <= n <= 231 - 1
1 <= pick <= n
Explanation
Do a binary search to find the pick.
Python Solution
# The guess API is already defined for you.
# @param num, your guess
# @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
# def guess(num: int) -> int:
class Solution:
def guessNumber(self, n: int) -> int:
start = 1
end = n
while start + 1 < end:
mid = start + (end - start) // 2
if guess(mid) == 0:
return mid
elif guess(mid) == -1:
end = mid
else:
start = mid
if guess(end) == 0:
return end
if guess(start) == 0:
return start
- Time Complexity: O(log(N)).
- Space Complexity: O(1).