Description
https://leetcode.com/problems/single-row-keyboard/
There is a special keyboard with all keys in a single row.
Given a string keyboard
of length 26 indicating the layout of the keyboard (indexed from 0 to 25), initially your finger is at index 0. To type a character, you have to move your finger to the index of the desired character. The time taken to move your finger from index i
to index j
is |i - j|
.
You want to type a string word
. Write a function to calculate how much time it takes to type it with one finger.
Example 1:
Input: keyboard = "abcdefghijklmnopqrstuvwxyz", word = "cba" Output: 4 Explanation: The index moves from 0 to 2 to write 'c' then to 1 to write 'b' then to 0 again to write 'a'. Total time = 2 + 1 + 1 = 4.
Example 2:
Input: keyboard = "pqrstuvwxyzabcdefghijklmno", word = "leetcode" Output: 73
Constraints:
keyboard.length == 26
keyboard
contains each English lowercase letter exactly once in some order.1 <= word.length <= 10^4
word[i]
is an English lowercase letter.
Explanation
Subtract previous index and add time.
Python Solution
class Solution:
def calculateTime(self, keyboard: str, word: str) -> int:
mapping = {}
for i, c in enumerate(keyboard):
mapping[c] = i
total_time = 0
prev = 0
for c in word:
index = mapping[c]
total_time += abs(index - prev)
prev = index
return total_time
- Time Complexity: O(N)
- Space Complexity: O(N)